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Mathematics 19 Online
OpenStudy (anonymous):

help with the following sequence

OpenStudy (anonymous):

\[a _{n}=e ^{2n/(n+2)} \]

OpenStudy (anonymous):

I ln both side ( after putting the limit) and then used the hospital rule but my book solved it in a completely different way :/ and came to a different answer. So, I'm kinda lost on how to solve it

OpenStudy (anonymous):

multiplied ln to both side*

OpenStudy (anonymous):

what does "solve" mean in this context?

OpenStudy (anonymous):

you have \[a_n=e^{\frac{2n}{n+2}}\] what are you trying to find?

OpenStudy (anonymous):

if you are looking for \[\lim_{n\to \infty}e^{\frac{2n}{n+2}}\] then since \[\lim_{n\to \infty}\frac{2n}{n+2}=2\] the answer is \(e^2\)

OpenStudy (anonymous):

Sorry I was gone for a while but yea it was what I was looking for^^

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