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Mathematics 14 Online
OpenStudy (anonymous):

which of the following is true

terenzreignz (terenzreignz):

I see two correct answers...

OpenStudy (anonymous):

okay .. which one and how plse explain

terenzreignz (terenzreignz):

p, q, and r are all true, right?

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

any idea

terenzreignz (terenzreignz):

if p and q is true... then... p and q is true LOL

terenzreignz (terenzreignz):

So that means \[\huge (p\land q)\] would be correct.

terenzreignz (terenzreignz):

Hello...?

terenzreignz (terenzreignz):

Is that so?

terenzreignz (terenzreignz):

I mean, p, q, and r, are all true.

terenzreignz (terenzreignz):

p statement is "4 is an even number" which is true... therefore p is true.

terenzreignz (terenzreignz):

I guess so?

terenzreignz (terenzreignz):

Actually, you can... that's called Logical Conjunction... \[P\\Q\\\therefore P\land Q\]

terenzreignz (terenzreignz):

It doesn't matter. My point is, we are given these... \[P\\Q\\R\] And logically we can conclude \[P\land Q\] I am not saying this is the only conclusion, but this is A correct conclusion to draw, nevertheless.

terenzreignz (terenzreignz):

We are not asked to form a tautology, we are merely asked which of the four choices is true.

terenzreignz (terenzreignz):

Excuse me?

terenzreignz (terenzreignz):

It's okay.

terenzreignz (terenzreignz):

This comes from a misunderstanding. I withhold my statement until @msingh clears this up. But I firmly stand by my interpretation that p is the variable representing the statement "4 is an even number" (implying p is true) and so on.

terenzreignz (terenzreignz):

Then, please, next time, do not be so quick to judge other people's reasoning as ridiculous, particularly if you do not know the answer yourself, and regardless, it is simply not polite.

OpenStudy (anonymous):

friends plse cooperate , we here are to study and help each other , plse i request both of u

terenzreignz (terenzreignz):

@msingh You're here after all... Perhaps you can clear this up... what exactly are p, q, and r?

OpenStudy (anonymous):

i really don't know i want to also clear this query asap

OpenStudy (anonymous):

@hoa , i know

terenzreignz (terenzreignz):

Perhaps you can show me a sample problem which is similar, and with its answer.

OpenStudy (anonymous):

this is the main pblm , i didn;t get anything simialr to it

terenzreignz (terenzreignz):

@Hoa I still do not fancy my reasoning being called ridiculous.

terenzreignz (terenzreignz):

Is there only one answer, @msingh ?

OpenStudy (anonymous):

yes

terenzreignz (terenzreignz):

Let me just rewrite it here... If p: 4 is an even number q: 6 is a divisor of 12 r: HCF of 4 & 6 is 2 then which of the following is true? \[\large a) \quad (p\land q)\\ \large b)\quad (p\lor q)\land \lnot \ r\\\large c)\quad \lnot \ p\lor (q\land r)\\\large d) \quad \lnot \ (q\land r)\lor p\]

terenzreignz (terenzreignz):

So, @msingh my question, mainly, is that, are p, q, and r taken to be variables representing the statements adjacent to them? Namely that p is the the statement "4 is an even number" ? etc

OpenStudy (anonymous):

yes

terenzreignz (terenzreignz):

Well, that does pose a problem, see, with that logic, all but (b) are true....

terenzreignz (terenzreignz):

Take for instance, (a) 4 is an even number AND 6 is a divisor of 12... The statement is true, no?

OpenStudy (anonymous):

okay

terenzreignz (terenzreignz):

as for (b) (4 is an even number OR 6 is a divisor of 12) AND 2 is not the HCF of 4 and 6

OpenStudy (anonymous):

okay

terenzreignz (terenzreignz):

well, what can you say about statement (b) ?

OpenStudy (anonymous):

hmm, i got it

terenzreignz (terenzreignz):

Well?

OpenStudy (anonymous):

b) option is answer

terenzreignz (terenzreignz):

But I thought you were being asked which statement was true? And (b) is false...

OpenStudy (anonymous):

kk

terenzreignz (terenzreignz):

unfortunately, a, c, and d all seem to be true...

OpenStudy (anonymous):

so which one is true

OpenStudy (anonymous):

okay

terenzreignz (terenzreignz):

And there's my problem, unless you can clear that up with a previous and similar item... sorry :)

OpenStudy (anonymous):

its okay bro,

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