Question

how to differentiate sin^2(2x+1)

Answer 1

Let sin(2x+1) = u
then dy/dx = 2u du/dx
= 2sin(2x+1) d(sin(2x+1))/dx

Answer 2

If you know the chain rule,then it's awesome.

Answer 3

i know the chain rule but am getting 4sin(2x+1)

Answer 4

answer given is 2sin(4x+2)

Answer 5

it should be 4cos(2x+1) .. oh my god

Answer 6

It is because :

\[2\sin(x) \cos(x) = \sin(2x)\]

Answer 7

Answer is right..

Answer 8

thank you waterineyes
i got my answer :D

Answer 9

\[\frac{d}{dx}\sin^2(2x + 1) \implies 2\sin(2x + 1) \cdot \cos(2x + 1) \cdot 2\]
\[\implies 2 \cdot 2\sin(2x + 1) \cos(2x + 1) \implies 2 \sin(2(2x + 1)) \implies 2 \sin(4x+2)\]

Answer 10

You are welcome dear..