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Entropy
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Problem: An evaporator has R-410a at -20 C and quality 20% flowing in, with the exit flow being saturated vapor at -20 C. Consider the heating to be a reversible process and find the specific heat transfer from the entropy equation.
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what does 20% quality infer?
it is the mass of the vapor divided by the mass of the total mixture
hmm what equation would you use? dS=q/T ?
rate equation for entropy: rate of change=+in -out+generation?? Scv=sum(mass flow in *sin)-sum(mass flow out*sout)+sum(Qcv/T)+Sgen
hm you can assume to have 100 grams then take 20%.. as for the rest it seems that you have too many unknown entropy values
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would i need to solve the entropy equation for Q?
yes
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