Question

Can anyone please help?
http://prntscr.com/11zddy

Answer 1

multiply the first fraction by (1-sin \(\theta\))/ (1-sin \(\theta\))

multiply the 2nd fraction by (1+sin \(\theta\))/ (1+sin \(\theta\))

can you do that ?

Answer 2

phi fraction remains the same

Answer 3

Its B

Answer 4

For the first fraction, if you multiply out
\[ \frac{1}{1+sin\theta}\cdot \frac{1-sin\theta}{1-sin\theta} \]
what do you get ?

the top is just 1- sin θ

what do you get for the bottom?

Answer 5

It is good to remember that (a+b)(a-b) is a^2 - b^2
in this case a is 1 and b is sinθ

Answer 6

2

Answer 7

the bottom is not 2.

Answer 8

What is the simplified form of sin(x + p)?

Answer 9

Its sinx or -sinx