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Mathematics 30 Online
OpenStudy (anonymous):

To solve |3x+2|<4, split the equation into 3x + 2 < 4 and 3x + 2 < -4 3x + 2 < 4 and 3x + 2 > - 4 3x - 2 < 4 and 3x - 2 > - 4 3x + 2 < - 4 and 3x + 2 > 4

OpenStudy (anonymous):

Is it 3x + 2 < 4 and 3x + 2 < -4 ? (The first choice)

OpenStudy (anonymous):

need help

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

have answer choices

OpenStudy (anonymous):

There up there with the question

OpenStudy (anonymous):

They're

OpenStudy (anonymous):

it's not the first choice. see how the inequality signs point the same way? the inequality signs should point in opposite directions.

OpenStudy (anonymous):

do you see why?

OpenStudy (anonymous):

Yes, I do

OpenStudy (anonymous):

So then it'd be the second choice?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

an easy way to do this problem if you have a graphing calculator is to graph y=abs(3x-2)-4 (solve your equation for zero, then put y in instead of the zero)

OpenStudy (anonymous):

Ok, I'll try that!

OpenStudy (anonymous):

Could you help me with one more question?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

but I have a question for you afterward

OpenStudy (anonymous):

Ok!

OpenStudy (anonymous):

Which domain number causes this relation not to be a function? R = { (-1, -1), (2, 0), (2, 1), (3, 1), (4, 4) } -1 zero 1 2

OpenStudy (anonymous):

how much do you already know about what is and is not a function?

OpenStudy (anonymous):

a relation is not a function if it has two y-values for one x-value.

OpenStudy (anonymous):

I thought it was 1?

OpenStudy (anonymous):

domain is x-values which x-value appears twice and has two different y-values?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Ok, your question?

OpenStudy (anonymous):

I pm'd it to you

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