To solve |3x+2|<4, split the equation into
3x + 2 < 4 and 3x + 2 < -4
3x + 2 < 4 and 3x + 2 > - 4
3x - 2 < 4 and 3x - 2 > - 4
3x + 2 < - 4 and 3x + 2 > 4
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Is it 3x + 2 < 4 and 3x + 2 < -4 ?
(The first choice)
OpenStudy (anonymous):
need help
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
have answer choices
OpenStudy (anonymous):
There up there with the question
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
They're
OpenStudy (anonymous):
it's not the first choice. see how the inequality signs point the same way? the inequality signs should point in opposite directions.
OpenStudy (anonymous):
do you see why?
OpenStudy (anonymous):
Yes, I do
OpenStudy (anonymous):
So then it'd be the second choice?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
an easy way to do this problem if you have a graphing calculator is to graph y=abs(3x-2)-4 (solve your equation for zero, then put y in instead of the zero)
OpenStudy (anonymous):
Ok, I'll try that!
OpenStudy (anonymous):
Could you help me with one more question?
OpenStudy (anonymous):
sure
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
but I have a question for you afterward
OpenStudy (anonymous):
Ok!
OpenStudy (anonymous):
Which domain number causes this relation not to be a function?
R = { (-1, -1), (2, 0), (2, 1), (3, 1), (4, 4) }
-1
zero
1
2
OpenStudy (anonymous):
how much do you already know about what is and is not a function?
OpenStudy (anonymous):
a relation is not a function if it has two y-values for one x-value.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I thought it was 1?
OpenStudy (anonymous):
domain is x-values
which x-value appears twice and has two different y-values?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Ok, your question?
Still Need Help?
Join the QuestionCove community and study together with friends!