Question

five children are arranged in a row of swings. how many different arrangements are possible?

Answer 1

5!=120.

The first child can choose all 5 swings, the 2nd child 4 swings, 3rd childe 3 swings, etc.

so it is 5*4*3*2*1=120.

Answer 2

@rrrrr i am confused about the 5! ? that doesn't make sense. how do i sovle that?

Answer 3

5! just means you start with 5 and multiply it with 4, 3, 2, 1 to get 120

Answer 4

another example

8! = 8*7*6*5*4*3*2*1

in general, you start with the number and you move down until you hit 1 (multiplying each number)

Answer 5

5! is five factorial which basically means that it is 5*4*3*2*1.
4! is four factorial which means that it is 4*3*2*1.
and such and such

Answer 6

and how do u solve 9! ??

Answer 7

8! = 8*7*6*5*4*3*2*1

9! = 9*8*7*6*5*4*3*2*1

etc etc

Answer 8

9! is 9*8*7*6*5*4*3*2*1.
n! is n*n-1*n-2*n-3*n-4*n-5...*5*4*3*2*1.

Answer 9

okay then. thankyou

Answer 10

youre welcome