Question

Mutiply:
1) x^2+8x+15/x^2+3x x x^2/2x+10
2)x^2-9/x^2+x-12 x x^2-16

Answer 1

\[1) \frac{ x^{2}+8x+15 }{ x^{2}+3x} \times \frac{ x^{2} }{ 2x+10 }\]

Answer 2

\[2)\frac{ x^{2}-9 }{x^{2}+x-12 } \times x^{2}\]

Answer 3

first, factor everything.

Answer 4

So I factor what adds to what and multiples to what?

Answer 5

factor the first part of 1)

Answer 6

Yes I understand, but do I factor what adds to 8 and multiples to 15? I'm brainwashed right now @_@.

Answer 7

And if that's correct, it would be 5 & 3.

Answer 8

yes, you do. factor *everything*

Answer 9

Okay so the first line would look like x(x+3)(x+5)?

Answer 10

x^2(x+3)(x+5)

Answer 11

Okay, how do I factor below the x^2 + 3x?

Answer 12

x(x+3)

Answer 13

and you can factor a 2 out of the denominator of the other fraction

Answer 14

How would that look? er sorry lol .

Answer 15

2(x+5)

Answer 16

\[\frac{ x^{2}(x+3)(x+5) }{x(x+3)} \times \frac{ x^{2} }{ 2{(x+5)} }\]

Answer 17

So then, the x+3 cancels out.

Answer 18

Do the x squared's cancel out & the x+5 or not?

Answer 19

then you cancel

Answer 20

?

Answer 21

x^3 / 2?

Answer 22

yes

Answer 23

now the next one?

Answer 24

or can you do that yourself?

Answer 25

isn't 1st just x/2 ??

Answer 26

Hartnn is gonna help me out. So I can move on to division.

Answer 27

quite sure, 1st = x/2

Answer 28

thank you hartnn, I was again making a stupid error.