Question

Find the absolute (global) Maximum and absolute (global) Minimum values of the function f(x)= (x^2)/(x^2-9) on the interval [-2,1].

Answer 1

check \(f(-2), f(1)\) and then find the critical point by finding the derivative, set it equal to zero and solve
check the function evaluated at that number as well

Answer 2

f(-2)= -4/5 f(1)= -1/8.. the derivative is (2x(x^2-9)-x^2(2x))/(x^2-9)^2

Answer 3

-18x/(x^2-9)^2=0

Answer 4

x=0

Answer 5

an easy solution to this problem is to use some graphing software and graph it...