Hey, I'm trying to do some study for my exams this week, I'm just looking at a sample paper, I get the general idea, but I'm not quite sure on the wording of iii, iv and vi b. A car passes a point p and applies its brakes at t=0 seconds. The car’s distance, s, from p at any subsequent time t is given by s = 20 t – 2 t2 where s is measured in metres and t in seconds. Find i. the distance of the car from p after 4 seconds ii. the speed of the car at t = 4 iii. the car’s speed as it passed through p iv. the time at which the car comes to rest vi. the constant acceleration of car
sorry not good at this kind of math
It seems you're given \[\large s(t) = 20t - 2t^2\]right?
This is what's called the position function.
The velocity (speed) function is simply the derivative of the position function with respect to time (t) \[\large v(t) = \frac{d}{dt}s(t)=s'(t)=20-4t\]
And finally, the acceleration function is the derivative of the velocity function, or the second derivative of the position function, with respect to time... \[\large a(t) = \frac{d}{dt}v(t)=\frac{d^2}{dt^2}s(t)=s''(t)=v \ '(t)=-4\]
So, I take it the questions are now readily doable? @Wilde1 :D
@terenzreignz - You've just saved me a lot of heartbreak on the last one, though I'm still puzzled by the wording of iii and vi, it's my understanding if iii is looking for the point p at which t = 0 then it'dd work out as v(0) = d / dt s(0) = 20 - 4(0) = 20
Okay, first off, you're asked for the speed (velocity) right? So you use the function v(t) = 20 - 4t And at the point p, t = 0 So... v(0) = 20 You were correct in your suspicions... :) Don't doubt yourself XD
I've literally been looking at that for the last hour and I've been like "No, it can't be that simple."
Actually, just checked the time, three hours.
Well, it makes sense, right? Though you doubted yourself... what did you expect the answer to (iii) would be? 0? :D
It makes sense, but I've been so useless at math for far too long and trusting my own intuitions when it comes to numbers hasn't fared well for me in the past :P is iv. the time at which the car comes to rest 20 - 4t = 0 4t = 20 t = 5 ?
Well, it seems your good intuition is coming back to you. You are correct, by the way :)
By the way, why did you skip (v) Your teacher not a big fan of five? :D
I'll be a Chemist yet :P *shakes fist* Thank you very much for your help, v. is related to the distance from p when it comes to a rest which I figured was just i. with 5 seconds instead of 4
ahh okay :) Yes, you will be a Chemist!!! :D Too bad I'm no good in Chemistry :3
Well if you ever need any help with Chemistry, I'm here to help :P, I wouldn't say I'm terrible at math, just that I tend to over complicate things in my head when I read the damn questions,
I'll be signing off for a bit... hopefully I won't encounter anything in Chemistry that would actually force me to ask a question on this site :D Welcome to Openstudy, stick around, see if you can help some people out :) ------------------------------------------------------------------ Terence out
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