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Mathematics 18 Online
OpenStudy (anonymous):

Please help http://prntscr.com/1229cf

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

i dont understand u have the answer below

OpenStudy (anonymous):

is its solution correct

OpenStudy (anonymous):

@hartnn

hartnn (hartnn):

i think its correct. checking the sum again, just to be sure.

OpenStudy (anonymous):

http://prntscr.com/1229lg

hartnn (hartnn):

yes, thatssum=-6 was correct.

OpenStudy (anonymous):

http://prntscr.com/1229lg can you explain this one

hartnn (hartnn):

yeah....number of cycles means how many times the same part of graph repeats. like |dw:1366871834645:dw|

OpenStudy (anonymous):

2

hartnn (hartnn):

|dw:1366871879211:dw|

OpenStudy (anonymous):

for a its 2 cycles

hartnn (hartnn):

na...its just one cycle..

hartnn (hartnn):

because the curve increases and then decreases, it does not increase again for 2nd cycle

OpenStudy (anonymous):

ok for part b

hartnn (hartnn):

y = Asin ( w* theta ) has the period of T = 2pi /w here, y= 2 sin (theta) so, w=... ?

hartnn (hartnn):

could you find w ?

OpenStudy (anonymous):

?

hartnn (hartnn):

what is multiplied with theta ?

hartnn (hartnn):

inside "sin"

OpenStudy (anonymous):

its 2

OpenStudy (anonymous):

y=2 sin θ = 2 sin pi/2 = 2 X 1 = 2

hartnn (hartnn):

'2' is outside sin

hartnn (hartnn):

its like 2 sin (1*theta)

hartnn (hartnn):

so, w= 1 period = 2pi/ w = 2pi/1 = 2 pi

OpenStudy (anonymous):

so 2 pi for part b

hartnn (hartnn):

yes.

hartnn (hartnn):

in y=A sin (w theta), A is the amplitude so, in y= 2 sin theta, amplitude = 2

hartnn (hartnn):

period and amplitude you can verify from graph also. once cycle ends at 2p, so period = 2pi max. positive value of graph = 2, then amplitude = 2

OpenStudy (anonymous):

thanks a lot

hartnn (hartnn):

welcome :)

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