Mathematics
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OpenStudy (anonymous):
Please help
http://prntscr.com/1229cf
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OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
i dont understand u have the answer below
OpenStudy (anonymous):
is its solution correct
OpenStudy (anonymous):
@hartnn
hartnn (hartnn):
i think its correct.
checking the sum again, just to be sure.
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hartnn (hartnn):
yes, thatssum=-6 was correct.
hartnn (hartnn):
yeah....number of cycles means how many times the same part of graph repeats.
like |dw:1366871834645:dw|
OpenStudy (anonymous):
2
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hartnn (hartnn):
|dw:1366871879211:dw|
OpenStudy (anonymous):
for a its 2 cycles
hartnn (hartnn):
na...its just one cycle..
hartnn (hartnn):
because the curve increases and then decreases, it does not increase again for 2nd cycle
OpenStudy (anonymous):
ok for part b
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hartnn (hartnn):
y = Asin ( w* theta )
has the period of T = 2pi /w
here,
y= 2 sin (theta)
so, w=... ?
hartnn (hartnn):
could you find w ?
OpenStudy (anonymous):
?
hartnn (hartnn):
what is multiplied with theta ?
hartnn (hartnn):
inside "sin"
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OpenStudy (anonymous):
its 2
OpenStudy (anonymous):
y=2 sin θ = 2 sin pi/2 = 2 X 1 = 2
hartnn (hartnn):
'2' is outside sin
hartnn (hartnn):
its like 2 sin (1*theta)
hartnn (hartnn):
so, w= 1
period = 2pi/ w = 2pi/1 = 2 pi
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OpenStudy (anonymous):
so 2 pi for part b
hartnn (hartnn):
yes.
hartnn (hartnn):
in y=A sin (w theta), A is the amplitude
so, in y= 2 sin theta,
amplitude = 2
hartnn (hartnn):
period and amplitude you can verify from graph also.
once cycle ends at 2p, so period = 2pi
max. positive value of graph = 2, then amplitude = 2
OpenStudy (anonymous):
thanks a lot
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hartnn (hartnn):
welcome :)