Simplify the expression 4squareroot256z^16. Assume that all variables are positive. This is the rational and radical functions unit.

Question

jdoe0001 · Answer

$
4*\sqrt{256}*\sqrt{z^{16}} \implies 4*\sqrt{16^2}*\sqrt{z^{16}}
$ and thus $\sqrt{16^2}=16$ so :)

anonymous · Answer

Would I then have 4*16*z? By the way THANK YOU!!!

jdoe0001 · Answer

:D

jdoe0001 · Answer

well,  one more step

anonymous · Answer

So my answer would be 64z, correct?

jdoe0001 · Answer

keep in mind that $ z^{16} \implies z^{8*2} \implies z^8*z^2$

jdoe0001 · Answer

not sure if that made sense... wait a bit

anonymous · Answer

It made sense. I'm still trying to wrap my head around it though.

jdoe0001 · Answer

$z^{16} \implies z^{8*8} \implies \pmatrix{z^8}^2$, that, thus you can also get $z^8$ out

anonymous · Answer

OH I see where I went wrong. I saw z^16 as z^2, and that's how I got just z when I got the square root...

jdoe0001 · Answer

$$
4*\sqrt{256}*\sqrt{z^{16}} \implies 4*\sqrt{16^2}*\sqrt{z^{16}}\
z^{16} \implies z^{8*8} \implies \pmatrix{z^8}^2\
	ext{then }\
\
4\sqrt{16^2\pmatrix{z^8}^2}
$$

anonymous · Answer

so $$\sqrt{z^16}$$  completely simplified would be |dw:1366930071362:dw| ?
Also sorry my typing isn't very explanatory, I am just joining this site and am not quite sure how to make my equations clear