Question

The position of an object at time t is given by s(t) = -9 - 3t. Find the instantaneous velocity at t = 8 by finding the derivative.

Answer 1

Derive -9-3t. Do you know how to do that?

Answer 2

@galacticwavesXX not exactly ... instruct me ?

Answer 3

?

Answer 4

So you have s(t) = -9-3t the derivative would be s'(t) = -9-3t

Which is d/dt because it is in respect of t.

d/dt = nx^n-1

Answer 5

You understand what I wrote so far, correct?

Answer 6

yes carry on :) so far lol

Answer 7

still there?

Answer 8

Yea sorry open study on iPad is acting confused

Answer 9

okay so how is it done ?

Answer 10

to get the answer

Answer 11

We know that -9 is a constant and the derivative of a constant is 0. Also the power at t is 1 so now we can apply the rule d/dt = nx^n-1 where n is 1 because it is the power at t

Which would give you s'(t) = -3 at t = 8

Answer 12

thats it ? wow THANKS SO MUCH!

Answer 13

one more ?

Answer 14

You welcome

Ok

Answer 15

Here is the second one :)

Answer 16

Give me a min been a while since I done a problem like that

Answer 17

The vertical asymptote x=1

Answer 18

As x approaches 1 the limit goes to infinity

Answer 19

Those are the answers for that question