FInd the zeros of the function using Fundamental Theorem of Algebra, the Rational Root Theorem, Descartes' Rule of Signs, and the Factor Theorem. x^2 - 7x - 72 Please try your best to explain how you do this or just show your work, it will help me with the rest of the problems.
that function has not rational zeros
That's what I came up with too, what about complex zeros though?
no
the zeros are real
the problem says there can be complex zeros, i just have trouble finding them
the zeros r real just use a calculator or the quadratic formual and u will see
What i had to do for this assignment, is take a rectangular box, measure the lwh and find the volume: l:7 w:4 h:3 V:84 Then I had to rewrite the equation as if I were solving for length, with the volume plugged in: 84 = (4)(3)x
84 = 12x Then I had to rewrite the equation expressing the width and height of the object in terms of x plus or minus a constant. For example, if the height measurement is 4 inches longer than the length, then the expression for the height will be (x + 4), and I got: 84 = (x - 3)(x - 4) Then I had to write in standard form: 84 = x^2 - 4x - 3x +12 84 = x^2 - 7x + 12 0 = x^2 - 7x - 72 And then I had to write it as a function (f(x)): f(x) = x^2 - 7x - 72 Now I'm stuck trying to finish this, by finding the zeros of the function!
You missed out an x there. The equation should have been : 84 = (x-3)(x-4) x . not just (x-3)(x-4) . correct that and try again.
Oh wow! Thanks for that, I'll try again! And sorry about the mistake both of you!
You started with a real world object so you should have real numbers only as your answer.
okay, thanks!
I should get this once that was simplified? 0 = x^3 - 7x^2 + 12 - 84
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