Find vertices, foci and the main axis
(x^2/25)+(y^2/16)=1
Center=_____
Vertices=____
foci=______
main axis=___
Im guessing this is a hyperbola? So far I have:
Center: 0,0
Vertex: (x^2/25)=1
-- 25=x^2
-- x=+/-5
(5,0) (-5,0)
Is that right? How would I find the foci and main axis? please and thank you!!

Question

Find vertices, foci and the main axis
(x^2/25)+(y^2/16)=1
Center=_____
Vertices=____
foci=______
main axis=___
Im guessing this is a hyperbola? So far I have:
Center: 0,0
Vertex: (x^2/25)=1
-- 25=x^2
-- x=+/-5
(5,0) (-5,0)
Is that right? How would I find the foci and main axis? please and thank you!!

anonymous · Answer

no this is an ellipse not a hyberbola. An hyperbola has subtraction sign in there.

center is correct though. I haven't done conic sections in a while, thus I forget how to find vertices and what not, but I can draw what it looks like:|dw:1366948736661:dw

rajee_sam · Answer

this is an ellipse

rajee_sam · Answer

center (0,0)
vertex (-5,0), (5,0)
foci (3,0), (-3,0)
major axis is x axis = 2a = 10

anonymous · Answer

How would I find the answers for foci and major axis? can anyone explain? D:

terenzreignz · Answer

You have a value for both a and b, right?
Then... use this formula to get a new value, c.
$$\huge c= \sqrt{|a^2-b^2|}$$