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Mathematics 26 Online
OpenStudy (anonymous):

plsee Find the value of following

OpenStudy (anonymous):

ok. a simple trick should help you in this... take angles in this way <A=B-D,<C=B+D... that way you can get value of <B... also use the sin rule for the sides a,b and c. Hope this helps. try and let me know.

OpenStudy (anonymous):

can u plse solve this

OpenStudy (anonymous):

|dw:1366965914243:dw|

OpenStudy (anonymous):

let me help u... but u will have to give me the answers... As defined <A=B-D,<C=B+D Apply angle sum property (<A+<B+<C)=180 and get value of <B

OpenStudy (anonymous):

yes , i will

OpenStudy (anonymous):

angle B = 180 - (angle A+angle C)

OpenStudy (anonymous):

yes... <B=180-(<B-D +<B+D)=180-(2*<B) find <B from here

OpenStudy (anonymous):

angle B = 180 - (B-D+B+D) angle B = 180 - 2 angle B or 3 angle B = 180 angle B = 180/3 = 60

OpenStudy (anonymous):

wait from where D angle came

OpenStudy (anonymous):

<D is just a common difference for our arithmetic progression... not part of our triangle... Did u get that??

OpenStudy (anonymous):

@msingh - do u know the sine rule for angles in a triangle ??

OpenStudy (anonymous):

d = common difference = second term - first term

OpenStudy (anonymous):

wht about sine rule ??

OpenStudy (anonymous):

sinA/a = sinB /b= sinC/c

OpenStudy (anonymous):

@msingh - right... use this to get a/c and c/a in terms of their corresponding sines and evaluate the remaining expression to get the value :)

OpenStudy (anonymous):

okay

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