plsee Find the value of following
ok. a simple trick should help you in this... take angles in this way <A=B-D,<C=B+D... that way you can get value of <B... also use the sin rule for the sides a,b and c. Hope this helps. try and let me know.
can u plse solve this
|dw:1366965914243:dw|
let me help u... but u will have to give me the answers... As defined <A=B-D,<C=B+D Apply angle sum property (<A+<B+<C)=180 and get value of <B
yes , i will
angle B = 180 - (angle A+angle C)
yes... <B=180-(<B-D +<B+D)=180-(2*<B) find <B from here
angle B = 180 - (B-D+B+D) angle B = 180 - 2 angle B or 3 angle B = 180 angle B = 180/3 = 60
wait from where D angle came
<D is just a common difference for our arithmetic progression... not part of our triangle... Did u get that??
@msingh - do u know the sine rule for angles in a triangle ??
d = common difference = second term - first term
wht about sine rule ??
sinA/a = sinB /b= sinC/c
@msingh - right... use this to get a/c and c/a in terms of their corresponding sines and evaluate the remaining expression to get the value :)
okay
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