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Chemistry
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C4H5O5 + 3NaHCO3 -> C4H2Na3O5+ 3H2O + 3CO2 Information: n(NaHCO3)= 5,94 mol Maleic acid (MW: 134 g/mol) used 1.1 times more of the substance quantity of the acid than the base. How much malic acid (C4H5O5) to be used? Show calculation; give the result in g
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This i a normal Acid-base reaction
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