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in(x-6)=1 SHOW work !PLEASE !!!!
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\[\ln(x-6)=1\] rewrite in exponential form as \[e^{1}=x-6\] or \[e=x-6\] and solve for \(x\)
\[\log_{10}(m) = n \Rightarrow m = (10)^n \]
you should be able to go from \[b^x=y\] to \[\log_b(y)=x\] and back easily
\[(x-6) = (10)^1 \Rightarrow x = 10 + 6 = 16 \]
btw if you see \(\ln(x)\) you visualize it at \(\log_e(x)\)
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So my answer would be : 16 ?
No... follow up from sat... e = x - 6 and solve for x. Add 6 to both sides, and that should do it.
ln(x-6)=1 or we can write like this lnx/ln6=1 =>lnx=ln6 =>x=6
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