Question

Need someone to check my answer
\[\int\limits\limits_{16}^{49}\frac{ \ \sqrt{lnx} dx }{ x } \]

Answer 1

I got approximately 2.04

Answer 2

would it help if I did the steps?

Answer 3

yes please do

Answer 4

well i used substitution.
\[u=\ln x\]\[du=\frac{ dx }{ x }\]

Answer 5

\[\int\limits_{\ln16}^{\ln49}\sqrt{u}\times du\]

Answer 6

\[\frac{ 2 }{ 3 }u ^{3/2}\]

Answer 7

from ln 16 to ln 49

Answer 8

and i got 2.04

Answer 9

You did well then.

Answer 10

does this seem correct?

Answer 11

THe limits are 49 and 16 tho, not ln 49 and ln 16

Answer 12

he did an u substitution @Meepi, hence his limits are correct:
\[\Large u=\ln x \]
from x=16 to x=49

Answer 13

Your answer is correct @MATTW20

Answer 14

yeah wasn't looking my bad

Answer 15

Thank You :)

Answer 16

you're welcome