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Mathematics 20 Online
OpenStudy (anonymous):

i m posting some questions , plse some one answer

OpenStudy (anonymous):

@e.mccormick just want to confirm answer plseeeeeeeeeee

OpenStudy (e.mccormick):

OK. What did you do to this?

OpenStudy (anonymous):

i rationalise

OpenStudy (e.mccormick):

Very nice work. You can still multiply through with the \(\frac{\sqrt{6}}{\sqrt{6}}\) to finish rationalizing. You are certainly on t he right track for putting it in rational form.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

i got (root 30 -root 18 +root12)/ 12

OpenStudy (e.mccormick):

This is one of those odd facts in math. What you started with was very simple, and some math professors would call that the simplified form. However, the standard is to use fully rationalized from. So unless the professor says, "Roots on the bottom are OK." you must fully rationalize for it to be in simplified form. 18=3*3*2 12=2*2*3 You can pull parts of those out of the roots. 30=5*3*2 and is therefore just \(\sqrt{30}\)

OpenStudy (anonymous):

now, i got (root30/ 12) -(1/2root2)+(1/2root3)

OpenStudy (anonymous):

should i left it the sum till what i posted

OpenStudy (anonymous):

its becoming very..

OpenStudy (e.mccormick):

I think they would want it in:\[\frac{\sqrt{30}-3\sqrt{2}+2\sqrt{3} }{12}\]As simplified form.

OpenStudy (anonymous):

okay

OpenStudy (e.mccormick):

So you were very close. All we did was multiply through the last root on the bottom,. Then factor out the 3 and 2 from where they could come out of roots.

OpenStudy (anonymous):

okay @e.mccormick thank u

OpenStudy (e.mccormick):

no problem. I was jsut finishing something else so it took me a bt, but glad I could help.

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