Question

T(t)=63(.05)^(t/10)+19 . Where T is temperature, and t is time in minutes.


How long did it take for a sandwich to reach an internal temputure of 30 degrees.

I know that I have to substitute 30 into T. But I don't know how to solve for t. Please help and show steps.

Answer 1

30 = 63(0.5)^(t/10) + 19
11 = 63(0.5)^(t/10)
11/63 = (0.5)6(t/10)
ln(11/63) = (t/10)ln(0.5)

Should be able to solve from there.

Answer 2

I'm not able to solve from here. How would I do this. Please.

Answer 3

I get where you got everything from what I"m having trouble with is isolating
t.

Answer 4

As of right now I have 11/63=(.5)^t/10

Answer 5

Do you know logarithms?

Answer 6

Or at least what they are?

Answer 7

Nope.
I think we learn that next year.

Answer 8

makes me wonder why you're doing this now then :|

Answer 9

Agreed, the only way to solve for the independent variable t is to use logarithms.

Answer 10

Lol, Can you give me the jist of this? I probably have learned it but we don't call it logarithms.

Answer 11

http://www.purplemath.com/modules/logs.htm

Answer 12

so, you learned it "next year", but can't recall it in the present..... ooookkk

Answer 13

I haven't learned it. Its in next years curriculum im told...

Answer 14

We havent learned this. o.o Log business.

Answer 15

so, this exercise doesn't apply then

Answer 16

\[\log_{b}y = x ...... b^x=y \]

Answer 17

Thanks for your help I guess.