Write the negation of the following statements: (i) p: For every real number x , x 2 > x. (ii) q: There exists a rational number x such that x 2 = 2. (iii) r: All birds have wings. (iv) s: All students study mathematics at the elementary level.
Negation of a statement \[\huge \lnot(\forall x \quad f(x))=\exists x\lnot f(x)\] A negation turns a universal quantifier into an existential, and negates whatever was inside the quantifier. Similarly... \[\huge \lnot(\exists x \quad f(x))=\forall x \lnot f(x)\] A negation turns an existential quantifier into a universal, and negates whatever was inside.
Now, if \[\huge f(x) = x\rightarrow r\] then \[\huge \lnot f(x) = x \land \lnot r\]
(in English, the negation of the statement "if p then q" is p and not q.)
Thanks
That conditional negation may not have been necessary :D
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