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Dividing Polynomials by binomials? Not sure how to do this.
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\[(y^2-y+2) \div (y+2) \] This is one of my problems.
\[y+2\sqrt{y^2-y+2}\] That's not a square root, I know this is the first step.
you want a easy trick to get the answer quickly?
\[\frac{y^2-y+2}{y+2}=\frac{y^2+2y-3y+2}{y+2}\] \[=\frac{y^2+2y}{y+2}+\frac{-3y+2}{y+2}\] \[y+\frac{-3y+2}{y+2}\] now use the same gimmick for the second part
Thanks :)
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yw otherwise you have to just divide like you do with numbers
unless you know synthetic division, in which case it is even easier
1 -1 2 -2| -2 6 _______________ 1 -3 4 answer is \(y-3+\frac{4}{y+2}\)
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