Question

int_ tan^2 x dx

Answer 1

Use the identity
\[\tan^2x=\sec^2x -1\]
and we have
\[\int\limits \tan^2x dx=\int\limits\sec^2x dx -\int\limits dx\]
We know that
\[\frac{d \tan x}{dx}=\sec^2 x\]
Thus,
\[\int\limits \tan^2x dx=\int\limits\sec^2x dx -\int\limits dx=\tan x -x + C\]

Answer 2

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Answer 3

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