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Mathematics 13 Online
OpenStudy (anonymous):

(-4r^6s^15)^4

OpenStudy (jdoe0001):

thank you for sharing that :)

OpenStudy (anonymous):

ok can you help me

OpenStudy (jdoe0001):

what's the question?

OpenStudy (anonymous):

(-4r^6s^15)^15

OpenStudy (jdoe0001):

so, what are you supposed to do with that?

OpenStudy (anonymous):

power of monomials

OpenStudy (jdoe0001):

$$ (X^{\alpha}Y^{\beta})^{\theta} \implies (X^{(\alpha * \theta)}Y^{(\beta*\theta)}) $$

OpenStudy (anonymous):

ok i still dont get it

OpenStudy (jdoe0001):

(-4r^{6}S^{15})^{15} \implies (-4r^{(6*15)}S^{(15*15)})

OpenStudy (jdoe0001):

wooops

OpenStudy (jdoe0001):

$$ (-4r^{6}S^{15})^{15} \implies (-4r^{(6*15)}S^{(15*15)}) $$

OpenStudy (jdoe0001):

though originally you said you have \((-4r^{6}S^{15})^{4} \)

OpenStudy (anonymous):

yes

OpenStudy (jdoe0001):

ok, then it'd be $$ (-4r^{6}S^{15})^{4} \implies (-4r^{(6*4)}S^{(15*4)}) $$

OpenStudy (jdoe0001):

just multiply those exponents, and that's your expression

OpenStudy (anonymous):

ok did i got 23^4

OpenStudy (anonymous):

what you got

OpenStudy (jdoe0001):

\(23^4\) ?

OpenStudy (jdoe0001):

how did you get that?

OpenStudy (anonymous):

i dint wat you told me to do

OpenStudy (jdoe0001):

$$ (-4r^{6}S^{15})^{4} \implies (-4r^{\boldsymbol{(6*4)}}S^{\boldsymbol{(15*4)}}) $$ the exponents, see the "*"?, those only

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