Question

\[\sum_{k=0}^{5}(3j+2)\]
sum is equal to:______
Apparently the answer is 18j+12
How would I get that answer? Can anyone show me what to do, please? :O

Answer 1

That's supposed to be "k=0" but the equal sign looks like a negative

Answer 2

Looks like a trick question.
The summand (the thing that follows the giant sigma) does not involve any k.
So, it is a constant as far as k is concerned...

Answer 3

So... if it is a constant, then...
\[\huge \sum_{k=0}^n c=(n+1)c\]