\[\sum_{k=0}^{5}(3j+2)\] sum is equal to:______ Apparently the answer is 18j+12 How would I get that answer? D:
i think there is a typo here, but maybe not
since the index is \(k\) but there is a \(j\) after the sum, this just means multiply \(6\times (3j+2)\)
there is no \(k\) in \(3j+2\) so as far as the sum is concerned \(j\) is a constant, and you are just adding up 6 identical terms of \(3j+2\)
I typed it in correctly. The j was what confused me. But it does appear to be a constant, like you said!
ok, then i hope that explains why you get \(18j+12\)
Yes, it did help! Where would the "6" come from though?
literally it is \[3j+2+3j+2+3j+2+3j+2+3j+2+3j+2\]
six terms, because you have \(k=0,1,2,3,4,5\)
oh, that's right! Ok! Thank you so much! :)
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