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Mathematics 20 Online
OpenStudy (anonymous):

\[\sum_{k=0}^{5}(3j+2)\] sum is equal to:______ Apparently the answer is 18j+12 How would I get that answer? D:

OpenStudy (anonymous):

i think there is a typo here, but maybe not

OpenStudy (anonymous):

since the index is \(k\) but there is a \(j\) after the sum, this just means multiply \(6\times (3j+2)\)

OpenStudy (anonymous):

there is no \(k\) in \(3j+2\) so as far as the sum is concerned \(j\) is a constant, and you are just adding up 6 identical terms of \(3j+2\)

OpenStudy (anonymous):

I typed it in correctly. The j was what confused me. But it does appear to be a constant, like you said!

OpenStudy (anonymous):

ok, then i hope that explains why you get \(18j+12\)

OpenStudy (anonymous):

Yes, it did help! Where would the "6" come from though?

OpenStudy (anonymous):

literally it is \[3j+2+3j+2+3j+2+3j+2+3j+2+3j+2\]

OpenStudy (anonymous):

six terms, because you have \(k=0,1,2,3,4,5\)

OpenStudy (anonymous):

oh, that's right! Ok! Thank you so much! :)

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