Question

A population consists of 25 men and 25 women. A simple random sample (draws at random without replacement) of 4 people is chosen. Find the chance that in the sample

Answer 1

all the people are of the same gender

Answer 2

2 * (25 choose 4) / (50 choose 4)

Answer 3

oh thx dea...

Answer 4

nd wht about..there are more women than men

Answer 5

(1/2) [ 1 - (25 choose 2) * (25 choose 2) / (50 choose 4) ]

Answer 6

2 more sub parts...please help.
.the fourth person is a woman and
the third person is a woman, given that the first person and fourth person are both men

Answer 7

.the fourth person is a woman=0.5

Answer 8

and what about last part..

Answer 9

:(

Answer 10

i'l check...thnx a lot for the answers ..

Answer 11

the third person is a woman, given that the first person and fourth person are both men=
(25 choose 1)/ (48 choose 1)

Answer 12

the fourth person is a woman and
the third person is a woman, given that the first person and fourth person are both men

^^^is one of those fourths meant to be second? It's unclear exactly what you're asking...

If the first and second person are both men, then that means there's only 23 men left in the group, and 25 women... assuming you want the third and fourth people to be women.

From the remaining 25 women, choose two women, divided by from 48 people choose 2.

\[\Large P = \frac{ 25C2 }{ 48C2 }\]

Answer 13

yup...thts ryt...thnk u abhi_abhi nd agent0smith

Answer 14

now i got the concept...

Answer 15

On a true-false test, each question has exactly one correct answer: true, or false. A student knows the correct answer to 70% of the questions on the test. Each of the remaining answers she guesses at random, independently of all other answers. After the test has been graded, one of the questions is picked at random. Given that she got the answer right, what is the chance that she knew the answer?

Answer 16

wht function need to be applied....