A deck of cards consists of 8 blue cards and 5 white cards. A simple random sample (random draws without replacement) of 6 cards is selected. What is the chance that one of the colors appears twice as many times as the other?

Question

anonymous · Answer

@agent0smith m unable to give u reply...dnt no y..??

agent0smith · Answer

We need to get either: 4 blues and 2 whites:

from 8 blues, choose 4, from 5 whites, choose 2. Total is 13, so from 13 choose 6.
$$\Large \frac{ 8C4 \times 5C2 }{13C6  }$$

 or 4 whites and 2 blues..see if you can get this one :)

Then you add the two together.

anonymous · Answer

@agent0smith some server error i think..:(...

agent0smith · Answer

Yeah, i got that too :/

anonymous · Answer

i got tht 1 wrong...m gettin 0.0349...

agent0smith · Answer

Show your work for the second part, 4 whites 2 blue

anonymous · Answer

..the answer to this is 0.4895

anonymous · Answer

you need 4b 2w or 4w 2b = p 4b 2w + p 4w 2b

p 4b 2w = 40.79254%
p 4w 2b = 8.15851%

agent0smith · Answer

This is actually the work that those guys didn't show...$$\Large \frac{ 8C4 \times 5C2 }{13C6  } = 0.4079$$
$$\Large \frac{ 5C4 \times 8C2  }{ 13C6 } = 0.08159$$