I have

(-x^2 - p^2)e^xt*sin(pt+y) + (x^2 + p^2)x

where x,p and y are constants, and t is the variable. Is there anyway to simplify this and make it equate to 0??

Question

I have

(-x^2 - p^2)e^xt*sin(pt+y) + (x^2 + p^2)x

where x,p and y are constants, and t is the variable. Is there anyway to simplify this and make it equate to 0??

hartnn · Answer

(e^x)t or e^(xt)

anonymous · Answer

http://www5a.wolframalpha.com/Calculate/MSP/MSP8231b94h2h2dhfc22580000608gidi494h8679d?MSPStoreType=image/gif&s=58&w=250.&h=22.

hartnn · Answer

x,p,y are constants, so the form is 
Ae^(xt) sin (pt+y) +C = 0
why u want it = 0 ?

hartnn · Answer

X^2+p^2 gets cancelled out

anonymous · Answer

ok, this question probably seems a little incomplete, so i'll put the whole thing.

a(t) = e^(-xt)*sin(pt+y), where x, p and y are constants. 

Show that $$\frac{ d^2a }{ dt^2 } + 2x \frac{ da }{ dt } + (x^2+p^2)a = $$

anonymous · Answer

AAAAAAAND i just realised where I went wrong.

hartnn · Answer

great! 
just my presence is enough :P

anonymous · Answer

that last x in the question was supposed to be an a, and then it ALL makes sense :P I'm an idiot.

hartnn · Answer

yes, it does :)