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OpenStudy (anonymous):
If the formation of NaCl proceeds according to the following equation and change in enthalpy, what is the reaction and change in enthalpy for the decomposition of 2 moles of NaCl? Na + ½Cl2 -> NaCl, DH = -411 kJ In this one since it's asking to change from a formation to a decomposition I have to reverse the equation and swap the enthalpy sign. So, would it become 822 kJ?
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OpenStudy (chmvijay):
yaa ur right :)
OpenStudy (anonymous):
okay, that's what I thought. Thank you!!
OpenStudy (chmvijay):
ur welcome
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