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(dy/dx)+(y/3)=0 How do I get the y variables on one side? Thanks!
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You subtract them from one side to move it :)
\(\frac{ dy }{ dx } = \frac{ y }{ 3 } \rightarrow \frac{ dy }{ y } = \frac{ 1 }{ 3 }dx\) now integrate
so 3dy + ydx to start?
it should be negative \(\frac{1}{3}\) by th way
How can the y/3 turn into 1/3 I don't get it
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well -1/3
you wan to get dy annd 'y' together, and dx and'x' toether so u can integrate
all I did was play around with it using algebra.
I am so bad at algebra, I see what you did there, thank you sooo much!
@Luis_Rivera #swag
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Never take a 15 year break from mathmatics
cause you will spell even the word wrong! lol
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