what is the lower and upper limit of -e^-t^2 from 0 to 2?

Question

anonymous · Answer

i think we did this earlier. give me another :P

agent0smith · Answer

Do you mean the maximum and minimum values?

anonymous · Answer

Maximum and minimum ??? how ??? We need to integrate using substitution...
And yeah, it's already done :-)

agent0smith · Answer

...that's what I was asking, what he is actually trying to find. It looks like he already has the limits for integration.

anonymous · Answer

that is the limits of integration. The lower limit is 0 but I can't figure out the upper limit

agent0smith · Answer

what is the lower and upper limit of -e^-t^2 from 0 to 2? Isn't your upper limit 2...? @saloniiigupta95 do you know how to integrate it using substitution? I don't... $$\Large \int\limits_{0}^{2} -e^{-t^2} dt$$ http://www.wolframalpha.com/input/?i=integral+of+-e%5E-t%5E2

anonymous · Answer

The previous question posted was the same thing with a '2t' multiplied ...

agent0smith · Answer

Ah, that makes a colossal difference :P I'm not familiar with the error function, other than knowing it's the integral of anything involving e^x^2.

anonymous · Answer

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