1.Solve the inequality. Show your work. |r + 3| ≥ 7
Okay, whenever you see something of the form |a| ≥ b Your task will be to solve two inequalities, the first, simply removes the absolute value || a ≥ b and the other, will be to reverse the inequality, and multiply one side by -1 a ≤ -b
so a ≤ -b is the answer
No. Following that logic... You get two inequalities to solve. (1) Simply remove the absolute value sign || r + 3 ≥ 7 Please solve this inequality, for r.
4
r ≥ 4 That's one of them. Now, solve for the other inequality The one which switches the inequality, and multiplies the right side by -1 r+3 ≤ -7
?
The same way you got 4, now solve this r + 3 ≤ -7
r<=-10
Very good :) So, what's the interval notation for r ≥ 4 ? And what's the interval notation for r ≤ -10 ?
?
Interval notation, like for r ≥ 4, it would be \[\Large [4 , \infty)\]
{-10}
∣r+3∣≥7 ∗r+3≥7 r≥4 ∗-(r+3)≥7 -r-3≥7 -r≥10 r≤-10
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