1.Solve the inequality. Show your work.
|r + 3| ≥ 7
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terenzreignz (terenzreignz):
Okay, whenever you see something of the form
|a| ≥ b
Your task will be to solve two inequalities, the first, simply removes the absolute value ||
a ≥ b
and the other, will be to reverse the inequality, and multiply one side by -1
a ≤ -b
OpenStudy (anonymous):
so a ≤ -b is the answer
terenzreignz (terenzreignz):
No.
Following that logic...
You get two inequalities to solve.
(1) Simply remove the absolute value sign ||
r + 3 ≥ 7
Please solve this inequality, for r.
OpenStudy (anonymous):
4
terenzreignz (terenzreignz):
r ≥ 4
That's one of them.
Now, solve for the other inequality
The one which switches the inequality, and multiplies the right side by -1
r+3 ≤ -7
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OpenStudy (anonymous):
?
terenzreignz (terenzreignz):
The same way you got 4, now solve this
r + 3 ≤ -7
OpenStudy (anonymous):
r<=-10
terenzreignz (terenzreignz):
Very good :)
So, what's the interval notation for
r ≥ 4
?
And what's the interval notation for
r ≤ -10
?
OpenStudy (anonymous):
?
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terenzreignz (terenzreignz):
Interval notation, like for
r ≥ 4, it would be
\[\Large [4 , \infty)\]