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Mathematics 28 Online
OpenStudy (anonymous):

1.Solve the inequality. Show your work. |r + 3| ≥ 7

terenzreignz (terenzreignz):

Okay, whenever you see something of the form |a| ≥ b Your task will be to solve two inequalities, the first, simply removes the absolute value || a ≥ b and the other, will be to reverse the inequality, and multiply one side by -1 a ≤ -b

OpenStudy (anonymous):

so a ≤ -b is the answer

terenzreignz (terenzreignz):

No. Following that logic... You get two inequalities to solve. (1) Simply remove the absolute value sign || r + 3 ≥ 7 Please solve this inequality, for r.

OpenStudy (anonymous):

4

terenzreignz (terenzreignz):

r ≥ 4 That's one of them. Now, solve for the other inequality The one which switches the inequality, and multiplies the right side by -1 r+3 ≤ -7

OpenStudy (anonymous):

?

terenzreignz (terenzreignz):

The same way you got 4, now solve this r + 3 ≤ -7

OpenStudy (anonymous):

r<=-10

terenzreignz (terenzreignz):

Very good :) So, what's the interval notation for r ≥ 4 ? And what's the interval notation for r ≤ -10 ?

OpenStudy (anonymous):

?

terenzreignz (terenzreignz):

Interval notation, like for r ≥ 4, it would be \[\Large [4 , \infty)\]

OpenStudy (anonymous):

{-10}

OpenStudy (linyu):

∣r+3∣≥7 ∗r+3≥7 r≥4 ∗-(r+3)≥7 -r-3≥7 -r≥10 r≤-10

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