Question

how to calculate integration of 1/(x+2) ki power 2

Answer 1

\[ \int \frac{1}{(x+2)^2}dx\]???

Answer 2

if yes, let \(u = x+2\)

Answer 3

\[\int \frac{1}{u^2}du => \int u^{-2}du\]

Answer 4

\[=>\frac{u^{-1}}{-1}+c\]
Then sub back the \(u\)

Answer 5

if it is 6/(x+2) ki power 2 then

Answer 6

what is \(ki\)

Answer 7

i wrote the question

Answer 8

hmm..i dont understand; what is \(ki\) first??

Answer 9

6/(x+2) ki power 2

Answer 10

ka integration

Answer 11

6/(x+2) ki power 2 ka integration, pls help

Answer 12

so \[\int \frac{6}{x+2}du\]
u = \(x+2\) => \[\frac{du}{dx} =2\]

Answer 13

you mean [6/(x+2) ]^2 dx
or 6 / (x+2)^2 dx ?

Answer 14

upar wala

Answer 15

means the upper one

Answer 16

english me bol na

Answer 17

yes

Answer 18

its same as your original Q
just 6 is multiplied -_-

Answer 19

but the answer does not match by that way why?
and the answer is 3x/x+2

Answer 20

guru hoza shuru jadu ki chhadi ghumao aur answer batao

Answer 21

integral of 6 / (x+2)^2 dx is -6/(x+2).
and its correct.

Answer 22

-6/(x+2) +c

Answer 23

that means the answer behind the book is wrong

Answer 24

must be