How many liters of methane gas (CH4) need to be combusted to produce 8.5 liters of water vapor, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem. CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)
Please post this in Chemistry.
I did ..... Im new to openstudy
Hi, I can see that you are a new member here at OpenStudy so, I would first like to say Welcome to OpenStudy, I would like to point you to the chat pods these chat pods are where you can make new friends and talk to new people just like you, I would also like to emphasize our "NON-CHEATING POLICY" we ask here at OpenStudy that you do NOT post exam/Test questions if you are caught doing this we will notify your current school I would also like to ask you to check out the OpenStudy "Code of Conduct" http://openstudy.com/code-of-conduct Please read this carefully and thoroughly. If you need any help feel free to message me or any other ambassador. Welcome to the OpenStudy Community! Ambassador SWAG
Hello Adjeharris, and welcome to Openstudy. The answer to your question, according to my calculations, would be 26.6L H2O. I know this from the fact that for every one molecule of combusted methane, there are two vapor molecules, so it would end up going to 13.3 : 26.6. I hope this helped with your answer. Next time remember to submit your question to the subject adjacent it to by clicking the "find more subjects" button, after you do that i'd suggest you take a look around the website and get familiar -- You can chat with other users by clicking the circle in the lower hand corner, surf subjects by following the steps ive provided previously, or answer others question to raise your smartscore! Have fun and happy learning!
ok thanks you guys!!!
Join our real-time social learning platform and learn together with your friends!