Question

Simplify x^4-3x^3/x^2-9

Answer 1

Ok, I think I got this.
\[\frac{x^4-3x^2}{x^2-9}\]
For this particular problem, you would want to factor both the top and bottom. Do you think that you could do that for me?

If You need help, I can certainly give it.

Answer 2

yea i got this x-3/x+3 i just wasnt sure if i was right

Answer 3

That is not the answer that I got.
For the top part of the function, we have
\[x^4 -3x^3\]
We can then take out an x^3 to get
\[x^3(x-3)\]
On the bottom we get (x+3)(x-3)
so we now have
\[\frac{x^3(x-3)}{(x-3)(x+3)}\]
Then after we cancel out like terms, we have
\[\frac{x^3}{(x+3)}\]
Does that make sense?

Answer 4

oooo ok yes i get it now :)
thnxs

Answer 5

no problem