vectors: solve x for AB=CD (vectors) A(x,1),B(4,x+3),C(x,x+2) and D(2x,x+6)
where should I start?

Question

vectors: solve x for AB=CD (vectors) A(x,1),B(4,x+3),C(x,x+2) and D(2x,x+6)
where should I start?

kinggeorge · Answer

Is this is saying that A=<x,1>?

anonymous · Answer

A(x,1) is a point. I guess is AB is (4-x,x+3-1), but it didn't work for me.

amistre64 · Answer

$$\vec{AB}=\vec{CD}$$

anonymous · Answer

the says the that x=2.

amistre64 · Answer

in other words:

B-A = D-C

amistre64 · Answer

of course i see no reason why A-B = C-D would not work equally as well

anonymous · Answer

yes $$\frac{ \rightarrow }{ AB}=\frac{ \rightarrow }{ CD}$$

amistre64 · Answer

A( x,    1 )        C( x  , x+2)
-B(-4,-x-3)     -D(-2x,-x-6)
---------        -----------
  (x-4,-2-x)  =   ( -x  , 0x-4)

so equate like components

x-4 = -x
-2-x = -4

anonymous · Answer

Ok. I did right, but in the end instead put x-4=-x I put x-4 -x =0 <--- wrong. Again thank you amistre64.

amistre64 · Answer

youre welcome