Question

vectors: solve x for AB=CD (vectors) A(x,1),B(4,x+3),C(x,x+2) and D(2x,x+6)
where should I start?

Answer 1

Is this is saying that A=<x,1>?

Answer 2

A(x,1) is a point. I guess is AB is (4-x,x+3-1), but it didn't work for me.

Answer 3

\[\vec{AB}=\vec{CD}\]

Answer 4

the says the that x=2.

Answer 5

in other words:

B-A = D-C

Answer 6

of course i see no reason why A-B = C-D would not work equally as well

Answer 7

yes \[\frac{ \rightarrow }{ AB}=\frac{ \rightarrow }{ CD}\]

Answer 8

A( x, 1 ) C( x , x+2)
-B(-4,-x-3) -D(-2x,-x-6)
--------- -----------
(x-4,-2-x) = ( -x , 0x-4)

so equate like components

x-4 = -x
-2-x = -4

Answer 9

Ok. I did right, but in the end instead put x-4=-x I put x-4 -x =0 <--- wrong. Again thank you amistre64.

Answer 10

youre welcome