Question

Solve the system of equations by graphing. 2x-y=2 , 5x+y=5

Answer 1

so graph it :)

Answer 2

you have to draw two lines and look at the intresection. did you do something already?

Answer 3

i just don't know the two plotting points for each equation :/

Answer 4

take one equation and make it look like "\(y = ax + b\)". For example the first equation becomes \(y=2x-2\). This should enable you to draw the line.

Answer 5

would it be (0,-2) (0,2)?

Answer 6

for the first one

Answer 7

oops. "y=2x-2" so if x=1, then y=2-2=0.

Answer 8

so then what would be the two plotting points for the first one?

Answer 9

@reemii

Answer 10

to draw the line you have to methods
1) find two points of the line and draw it
2) "y=2x-2" tells that the slope is equal to 2 and the line cuts the y-axis at (0,-2).

you do the first method. when x=0 you get y=-2, when x=1, y=0.
so the points are (0,-2) and (1,0).

Answer 11

there's no prefered choice for taking the two points, you just have to choose 2 different values for \(x\) and find the corresponding \(y\). It is often simple to take \(x=0\) and \(x=1\).

Answer 12

Is it working well for the other equation?

Answer 13

the second one would be y=5x+5?

Answer 14

@reemii

Answer 15

there's a minus sign missing.

Answer 16

so then it would be y=5x-5?

Answer 17

rather \(y=-5x+5\). The operation to obtain it was to -remove 5x- on both sides.
Now you get two points and you'll be able to draw the second line.

Answer 18

oh ok. so the plotting points for this one would be (0,5) (0,-5)

Answer 19

how do you obtain these points?

Answer 20

explain the process, because one point is ok, the other isn't.

Answer 21

or would it be (1,0)?

Answer 22

(1,0) yes! and (0,-5) was wrong.

Answer 23

:) so (1,0) and (0,5)?

Answer 24

@reemii

Answer 25

that's right. can you finish the problem?

Answer 26

Thank you so much! yes i did :)

Answer 27

congrats ;)