Question

From a cruising depth of 75 m below sea lever (BSL) the Nautilus descended to 105 m BSL and then rose to 80 m BSL. What is the total vertical distance the Nuatilus traveled?

Another Question -

A red kangaroo jumps along 40 km/h. At this rate how long would it take to jump 2 km in minutes?

Answer 1

I have a couple more maths questions:
If r = 4, find the value of 3r - 9

4/7 x ? = 16

Answer 2

From 1 to 2, the vertical distance is 105 m - 75 m.
From 2 to 3, the vertical distance is 105 m - 80 m.
Do the two subtractions and add the results.

Answer 3

speed = distance divided by time
s = d/t
In your case, you know s, the speed of 40 km/h and the distance, 2 km, and you are looking for the time. Solve s = d/t for t:
s = d/t
Multiply both sides by t
st = d
Divide both sides by s
t = d/s
Now substitute the known values for d and s:
t = 2 km / (40 km/h) = 0.05 h
The result is in hours. To get minutes, multiply hours by 60:
t = 0.05 * 60 minutes = 3 minutes

Answer 4

@mathstudent55 thank you soooooo much! that really helped me