Write the expression ln+ 3x^2/(x+3)^5 in an equivalent form that has no powers, products, or quotients in it. I got ln3x^2−ln(x+3)^5=2ln3x−5ln(x+3)

Question

anonymous · Answer

"−5ln(x+3). The underlined section is correct. The other part is almost. You wrote it as if (3x)2 not as written 3x2. also break down the 3 x" I don't understand what I did wrong.

e.mccormick · Answer

3 is not squared in the first one.

e.mccormick · Answer

$$\frac{3x^2}{(x+3)^5}\implies \
ln\left(\frac{3x^2}{(x+3)^5}\right)\implies \
ln(3x^2)-ln(x+3)^5\implies \
ln(3)+ln(x^2)-5 ln(x+3)\implies \
ln3+2lnx-5 ln(x+3)$$

e.mccormick · Answer

It was not $(3x)^2$.  So the 3 was not squared, it was multiplying.