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Complete the following proof. Prove: The diagonals of a square are perpendicular. https://media.glynlyon.com/o_geo_2010/9/q417a.gif
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find the slope of AC and BD adn see that their product is -1
but how do i find the slope of them?
slope of line joining A(0,0) and C(a,a,) is m1 = (a-0)/(a-0)= 1
slope od line joining B (a,0) and D (0,a) is m2= (a-0)/(0-a) =-1
so those are my slopes? how did you get numbers from letters?
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thus the product of the slopes of AC and BD is -1 hence AC and BD are at right angles
slope of line joining (x1,y1) and (x2,y2) is given by (y2-y1)/(x2-x1)
thank you so much for your help!
welcome dear
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