A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C, how much of the substance was present?

3.88 kg

32.3 g

3.88 g

32.3 kg

Question

A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C, how much of the substance was present?
 	
	
3.88 kg
	
32.3 g
	
3.88 g
	
32.3 kg

aaronq · Answer

q=CmdT

aaronq · Answer

you would be solving for mass, m.

anonymous · Answer

so what am I suppose to do?

aaronq · Answer

plug it into the formula and solve for mass, m, as the question asks.

anonymous · Answer

but what numbers am I suppose to plug in?

aaronq · Answer

The ones given...138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C lol

anonymous · Answer

yeah I know that But I am lost on where to plug them in.. sorry Im not understanding this..

aaronq · Answer

q=heat=energy =138 kilojoules (don't forget to convert to joules)

going from 298 to 303 Kelvin so, 

T(initial=298 K
T(final)=303K

specific heat (C) = 7.11 J/g·°C

anonymous · Answer

So 3.88 kg?

aaronq · Answer

idk i didn't work it out

anonymous · Answer

oh okay well thanks

aaronq · Answer

no problem, if you write it, il tell you if you set it up correctly