p(x)=x^4-x^3-5x^2-x-6, given that i is a zero
multiply these toe factors together and write the product as a quadratic

Question

p(x)=x^4-x^3-5x^2-x-6, given that i is a zero 
multiply  these toe factors together and write the product as  a quadratic

agent0smith · Answer

"multiply  these toe factors together and write the product" maybe re-write this part... what two factors?

but i is a zero, which means (x-i) is a factor of the equation. I guess you could do long division or synthetic division.

anonymous · Answer

given that i is a zero , writ this zero and the conjugate zero as linear factor

anonymous · Answer

that is the first part

agent0smith · Answer

Ah, yes it will have a conjugate zero (x-i)(x+i)

So you just have to expand that.

anonymous · Answer

how

anonymous · Answer

This should help you: http://phdtutor.com/algebra/pre-calculus/linear_factorization_theorem.aspx

agent0smith · Answer

You know how to expand something like (x+2)(x-2) right? Do the same with (x-i)(x+i), it's a difference of two squares.

anonymous · Answer

ok