Question

medals and fans rewarded

Answer 1

\[3x^2=33x+24\]

Answer 2

@ajprincess @nubeer @.Sam. can you help me please

Answer 3

\(3x^2=33x+24\)
\(3x^2-33x+24=0\)
Use quadratic formula.
\[x=\frac{ -b\pm\sqrt{b^2-4ac} }{ 2a }\]
the values of a, b and c can be found by comparing the equation \(3x^2-33x+24=0\) with the general equation \(ax^2+bx+c=0\). Does that help? @ladiesman217

Answer 4

ya

Answer 5

**-24
dividing the entire equation by 3 would simplify calculations

Answer 6

it is actually \(3x^2-33x-24=0\). am sorry abt the mistake

Answer 7

ya. first factor out 3 and then divide by 3 both sides. After that use quadratic formula:)

Answer 8

the equation i got was\[\frac{ -(-3)\sqrt{3^{2}-4(3)(-24)} }{ 2*3 }\]

Answer 9

b=-33

Answer 10

this is the correct equation right
\[\frac{ -(-33)\sqrt{-33^{2}-4(3)(-24)} }{ 2*3 }\]

Answer 11

it will be
\[\frac{ -(-33)\sqrt{(-33)^2-4*3*(-24)} }{ 2*3}\]

Answer 12

i got\[\frac{ 11\pm \sqrt{153} }{ 2 }\]

Answer 13

ya right:)

Answer 14

good work:)

Answer 15

thnx

Answer 16

welcome:)