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Mathematics 17 Online
OpenStudy (anonymous):

d^3 * d^5 =??

OpenStudy (anonymous):

d^(3+5) = d^(8) its like the formula a^m * a^n = a^(m+n) Hope u understood

OpenStudy (andriod09):

Haha, this is great timing, I just went over this earlier. @sriramkumar said the right answer. The formula he gave is called the Product rule, where x^n+x^c=x^(n+c). The reasoning behind this is because D^3 can be simplified as (d*d*d). So when you have D^3+ D^5, you would add the exponents together. and you would get D^8. If you had something like this: (2d^3)^2, then you would do this: \[(2d^3)^2\]\[(4d^3)^2\]\[(4d^2)^3\] then all you would do is multiply the 2, and the 3 together, and you would get: \[(4d^6)\] Hope sriramkumar and I help you out in your studies! Thanks! Andy|Andriod09

OpenStudy (anonymous):

@andriod09 pleasure's mine to help :D thank You :D

OpenStudy (anonymous):

try wolframalpha.com its a big help for problems like that

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

d^8 since ^3 + ^5

OpenStudy (anonymous):

Long story short it is d^8. Just add that stuff up buddy. :)

OpenStudy (anonymous):

hey chris :D

OpenStudy (anonymous):

haha hey girl!

OpenStudy (anonymous):

wats up? lol

OpenStudy (anonymous):

lol message me?

OpenStudy (anonymous):

sure :)

OpenStudy (anonymous):

i did...

OpenStudy (anonymous):

When you are multiplying exponents you add them. So it would be d^8 power.

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