Find the function f(x) satisfying the given conditions. (HINT: You are finding the value of C)
Find \[\int\limits_{}^{}f'(x) dx=f(x)+C, \text{ where } (f)'=f'\]
Or evaluate
Integrate the function given to get from f' to f.
Don't forget when you integrate, put +C.
can u explain? :/
\[\int\limits_{}^{}f'(x) dx=\int\limits_{}^{}(4x^2-1) dx\] You may find it easy to use the following: \[\int\limits_{}^{}x^n dx =\frac{x^{n+1}}{n+1}+C, n \neq -1\] This is because \[(\frac{x^{n+1}}{n+1})'=(n+1) \cdot \frac{x^{n+1-1}}{n+1}=x^{n+1-1}=x^n\] And you may also want to use \[\int\limits_{}^{}k dx=kx+C \text{ where} K, C \text{ are a constant} \]
This is because (kx+C)'=(kx)'+(C)'=k(x)'+0+k(x)'=k(1)=k
okay thanks
Are you familiar with the idea of `Integration` yet? Or has it only been introduced to you as the process of finding the `anti-derivative` so far?
no i'm not familiar
@Best_Mathematician can u help?
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