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Mathematics 24 Online
OpenStudy (anonymous):

Find the function f(x) satisfying the given conditions. (HINT: You are finding the value of C)

OpenStudy (anonymous):

myininaya (myininaya):

Find \[\int\limits_{}^{}f'(x) dx=f(x)+C, \text{ where } (f)'=f'\]

myininaya (myininaya):

Or evaluate

myininaya (myininaya):

Integrate the function given to get from f' to f.

myininaya (myininaya):

Don't forget when you integrate, put +C.

OpenStudy (anonymous):

can u explain? :/

myininaya (myininaya):

\[\int\limits_{}^{}f'(x) dx=\int\limits_{}^{}(4x^2-1) dx\] You may find it easy to use the following: \[\int\limits_{}^{}x^n dx =\frac{x^{n+1}}{n+1}+C, n \neq -1\] This is because \[(\frac{x^{n+1}}{n+1})'=(n+1) \cdot \frac{x^{n+1-1}}{n+1}=x^{n+1-1}=x^n\] And you may also want to use \[\int\limits_{}^{}k dx=kx+C \text{ where} K, C \text{ are a constant} \]

myininaya (myininaya):

This is because (kx+C)'=(kx)'+(C)'=k(x)'+0+k(x)'=k(1)=k

OpenStudy (anonymous):

okay thanks

zepdrix (zepdrix):

Are you familiar with the idea of `Integration` yet? Or has it only been introduced to you as the process of finding the `anti-derivative` so far?

OpenStudy (anonymous):

no i'm not familiar

OpenStudy (anonymous):

@Best_Mathematician can u help?

OpenStudy (loser66):

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