Question

Find the first 5 terms of the sequence: an = (-1/2)n - 1

Answer 1

Do you understand? Yes. No. Maybe.

Answer 2

Maybe @some_someone

Answer 3

Have you done the other ones like how i did the first one? Try it and see :)

Answer 4

Okay. I'll try them @some_someone

Answer 5

Hold on... I did it wrong. Lemme try again

Answer 6

-1/2, 1/4, -1/8, 1/16 <----- This is my answer

Answer 7

So find:
when n = 1
when n = 2
when n = 3
when n = 4
when n = 5

Answer 8

\[a _{n} = \left( \frac{ -1 }{ 2 } \right)n - 1\]
when n = 1
\[a _{1} = \left( \frac{ -1 }{ 2 } \right)1 - 1\]
\[a _{1} = \left( \frac{ -1 }{ 2 } \right)0\]
\[a _{1} = 0 \]

Answer 9

\[a _{n} = \left( \frac{ -1 }{ 2 } \right)n - 1\]
when n = 2
\[a _{2} = \left( \frac{ -1 }{ 2 } \right)2 - 1\]
\[a _{2} = \left( \frac{ -1 }{ 2 } \right)1\]
\[a _{2} = \frac{ -1 }{ 2 }\]

Answer 10

I got my answer

Answer 11

\[a _{n} = \left( \frac{ -1 }{ 2 } \right)n - 1\]
when n = 3
\[a _{3} = \left( \frac{ -1 }{ 2 } \right)3 - 1\]
\[a _{3} = \left( \frac{ -1 }{ 2 } \right)2\]
\[a _{3} = -1\]

Answer 12

what did you get @Emilyh117

Answer 13

I got -1/2, 1/4, -1/8, 1/16 @some_someone

Answer 14

\[0, -\frac{ 1 }{ 2 }, -1....\]
these were the first three terms i found...
You still need to find the other two.

I didn't get what you got 0:

Answer 15

Did you look at the first three i did?

Answer 16

Yeah. Those weren't choices @some_someone

Answer 17

hmmm were the ones you found choices?

Answer 18

Yeah @some_someone

Answer 19

Is this the given:
\[a _{n} = \left( \frac{ -1 }{ 2 } \right)n - 1\]

Answer 20

Yes @some_someone

Answer 21

\[a _{n} = \left( \frac{ -1 }{ 2 } \right)n - 1\]
when n = 4
\[a _{4} = \left( \frac{ -1 }{ 2 } \right)4 - 1\]
\[a _{4} = \left( \frac{ -1 }{ 2 } \right)3\]
\[a _{4} = -\frac{ 3 }{ 2 }\]

Answer 22

\[a _{n} = \left( \frac{ -1 }{ 2 } \right)n - 1\]
when n = 5
\[a _{5} = \left( \frac{ -1 }{ 2 } \right)5 - 1\]
\[a _{5} = \left( \frac{ -1 }{ 2 } \right)4\]
\[a _{5} = -2\]