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Given the Shrodinger equation: \[i \hbar \frac{\partial}{\partial t} \psi(\vec{r},t) = \frac{- \hbar^2}{2m} \vec{\nabla}^2 \psi(\vec{r},t)\] With: \[\psi(\vec{r},t) = \int\limits_{\mathbb{R}^3} d^3 r U(\vec{r},\vec{r}',t)\psi(\vec{r}',0)\] and \[U(\vec{r},\vec{r}',t) = \sqrt{\frac{m}{i 2 \pi \hbar t}} e^{\frac{i m (\vec{r}-\vec{r}')^2}{2 \hbar t}}\] Find: \[\psi (\vec{r},t)\] Given: \[\psi(\vec{r},0) = C e^{i k_0 \vec{r}}e^{\frac{- \vec{r}^2}{2 a ^2}}\]
This one's a toughy :P I figured that the "I HAVE THE INTERCEPT AND THE SLOPE WHAT IS THE LINE?!?!?!?" 's get old lol
@zepdrix Help me! :P
Also @satellite73 since I haven't talked to you in literally a year, I wasn't sure if you were still here or not :P
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