Question

State the vertical asymptote of the rational function. f(x) =(x-8)(x+4)/x^2-9

Answer 1

What's going on in the denominator of the function at a vertical asymptote?

Answer 2

\[f(x)=\frac{ (x-8)(x+4) }{ x ^{2}-9 }\]

Answer 3

thats the equation

Answer 4

NoelGreco
Medals 0

What's going on in the denominator of the function at a vertical asymptote?

Answer 5

OK, but what value does the denominator of a function have at a vertical asymptote?

Answer 6

I dont know

Answer 7

The denominator is zero at a vertical asymptote. Solve x^2 - 9 =0. The solutionas are your vertical asumptotes.

Answer 8

I dont get it, sorry...

Answer 9

let me see if i get it

Answer 10

Factor the denominator.

Answer 11

What are the factors of x^2-9?

Answer 12

-+ 3

Answer 13

and if a letter is next to a number it means multiply

Answer 14

The factors are (x-3)(x+3)
Set each one equal to 0

Answer 15

x-3=0---> x=3
x+3=0---x>=-3
And those are the equations of your vertical asymptotes.

Answer 16

like he said that the way you do it

Answer 17

dose that help out